How do you solve Apply Bitwise Operations to Make Strings Equal on LeetCode?

Apply Bitwise Operations to Make Strings Equal (LeetCode #2546) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n) time complexity and O(1) space complexity. Key insight: If both strings have at least one '1', transformation is possible.

What is the time complexity of Apply Bitwise Operations to Make Strings Equal?

The optimal solution for Apply Bitwise Operations to Make Strings Equal runs in O(n) time and uses O(1) space. This complexity is linear because we are simply counting the number of '1's in each string, which requires a single pass through each string.

What is the brute force solution for Apply Bitwise Operations to Make Strings Equal?

The brute force approach for Apply Bitwise Operations to Make Strings Equal is Brute Force, with O(n²) time complexity and O(1) space complexity. The brute force approach involves trying every possible combination of index pairs to see if we can transform the string `s` into `target`. This method is straightforward but inefficient due to the large number of operations required. The optimal Optimal Solution approach improves this to O(n).

What algorithm or data structure is used to solve Apply Bitwise Operations to Make Strings Equal?

Apply Bitwise Operations to Make Strings Equal uses the following concepts: String, Bit Manipulation. The recommended patterns to study are: Bit Manipulation, Greedy.

What are the interview tips for Apply Bitwise Operations to Make Strings Equal?

Always think about edge cases, especially with binary operations. Explain your thought process clearly; it helps in case you need to pivot your approach. Practice recognizing patterns in problems; they often lead to optimal solutions.

What are common mistakes when solving Apply Bitwise Operations to Make Strings Equal?

Failing to consider cases where one string is all '0's and the other is not. Not recognizing that the operations can lead to multiple transformations, leading to incorrect assumptions.

#2546

Apply Bitwise Operations to Make Strings Equal

Medium

StringBit ManipulationBit ManipulationGreedy

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(n)
Space	O(1)	O(1)

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Intuition

Time O(n)Space O(1)

The optimal solution leverages the properties of binary strings and bitwise operations. We can determine if transformation is possible by checking the presence of '1's in both strings. If both strings have at least one '1' or both are all '0's, transformation is possible.

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Algorithm

2 steps

1Step 1: Count the number of '1's in both `s` and `target`.
2Step 2: If both counts are non-zero or both are zero, return true; otherwise, return false.

solution.py2 lines

1def canMakeEqual(s, target):
2    return (s.count('1') > 0 and target.count('1') > 0) or (s.count('1') == 0 and target.count('1') == 0)

ℹ

Complexity note: This complexity is linear because we are simply counting the number of '1's in each string, which requires a single pass through each string.

1If both strings have at least one '1', transformation is possible.
2If both strings are all '0's, transformation is also possible.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.