#1016
Binary String With Substrings Representing 1 To N
MediumHash TableStringBit ManipulationSliding WindowHash MapArray
Approaches
Brute ForceOptimal
Complexity Comparison
| Brute Force | Optimal Solution★ | |
|---|---|---|
| Time | O(n * m), where m is the average length of binary representations (up to 30). | O(n + m), where m is the number of unique binary representations. |
| Space | O(1) | O(n) |
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Intuition
Time O(n + m), where m is the number of unique binary representations.Space O(n)
The optimal approach leverages the fact that we only need to check binary representations up to 30 bits. We can use a set to store these representations and check them against the string s efficiently.
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Algorithm
4 steps- 1Step 1: Create a set to store binary representations of numbers from 1 to n.
- 2Step 2: Loop through numbers from 1 to n and add their binary representations to the set.
- 3Step 3: For each binary representation, check if it exists in the string s.
- 4Step 4: If all representations are found, return true; otherwise, return false.
solution.py5 lines
1# Full working Python code
2
3def queryString(s, n):
4 binaries = {bin(i)[2:] for i in range(1, n + 1)}
5 return all(b in s for b in binaries)ℹ
Complexity note: The time complexity is O(n + m) because we generate binary strings for numbers up to n and check them against s. The space complexity is O(n) due to storing binary representations.
- 1We only need to check binary representations up to 30 bits due to the limit of n.
- 2Using a set for storing binary representations allows for efficient membership checking.
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