How do you solve Calculate Score After Performing Instructions on LeetCode?

Calculate Score After Performing Instructions (LeetCode #3522) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n) time complexity and O(n) space complexity. Key insight: Tracking visited indices prevents infinite loops.

What is the time complexity of Calculate Score After Performing Instructions?

The optimal solution for Calculate Score After Performing Instructions runs in O(n) time and uses O(n) space. The complexity is linear as each instruction is processed once, and the set allows for O(1) average time complexity for checks.

What is the brute force solution for Calculate Score After Performing Instructions?

The brute force approach for Calculate Score After Performing Instructions is Brute Force, with O(n²) time complexity and O(1) space complexity. This approach simulates each instruction step-by-step, checking for revisits and updating the score. It can be inefficient due to potential revisits causing multiple checks. The optimal Optimal Solution approach improves this to O(n).

What algorithm or data structure is used to solve Calculate Score After Performing Instructions?

Calculate Score After Performing Instructions uses the following concepts: Array, Hash Table, String, Simulation. The recommended patterns to study are: Hash Map, Array.

What are the interview tips for Calculate Score After Performing Instructions?

Explain your thought process clearly. Consider edge cases like empty arrays. Optimize your solution after the brute force.

What are common mistakes when solving Calculate Score After Performing Instructions?

Forgetting to check for revisits. Incorrectly updating the score or index.

#3522

Calculate Score After Performing Instructions

Medium

ArrayHash TableStringSimulationHash MapArray

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(n)
Space	O(1)	O(n)

💡

Intuition

Time O(n)Space O(n)

This approach efficiently tracks visited instructions using a set, ensuring each instruction is processed only once. It leverages direct index manipulation for jumps.

⚙️

Algorithm

3 steps

1Step 1: Initialize score and a set to track visited indices.
2Step 2: Iterate through instructions, updating score and index based on instruction type.
3Step 3: Stop when out of bounds or revisiting an index.

solution.py14 lines

1def calculateScore(instructions, values):
2    score = 0
3    visited = set()
4    i = 0
5    while 0 <= i < len(instructions):
6        if i in visited:
7            break
8        visited.add(i)
9        if instructions[i] == 'add':
10            score += values[i]
11            i += 1
12        elif instructions[i] == 'jump':
13            i += values[i]
14    return score

ℹ

Complexity note: The complexity is linear as each instruction is processed once, and the set allows for O(1) average time complexity for checks.

1Tracking visited indices prevents infinite loops.
2Direct index manipulation allows efficient jumps.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.