How do you solve Calculator with Method Chaining on LeetCode?

Calculator with Method Chaining (LeetCode #2726) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(1) time complexity and O(1) space complexity. Key insight: Method chaining allows for cleaner and more readable code.

What is the time complexity of Calculator with Method Chaining?

The optimal solution for Calculator with Method Chaining runs in O(1) time and uses O(1) space. Each operation is performed in constant time since we are only updating a single variable (result).

What is the brute force solution for Calculator with Method Chaining?

The brute force approach for Calculator with Method Chaining is Brute Force, with O(1) time complexity and O(1) space complexity. In this approach, we will create a simple Calculator class that performs operations one at a time and returns the result after each operation. This method is straightforward but does not utilize method chaining effectively. The optimal Optimal Solution approach improves this to O(1).

What are the interview tips for Calculator with Method Chaining?

Clearly explain your thought process while coding. Make sure to test edge cases, such as division by zero. Practice writing clean and readable code.

What are common mistakes when solving Calculator with Method Chaining?

Forgetting to return 'this' for method chaining. Not handling division by zero correctly.

#2726

Calculator with Method Chaining

Easy

Method ChainingError Handling

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(1)	O(1)
Space	O(1)	O(1)

💡

Intuition

Time O(1)Space O(1)

The optimal solution is similar to the brute force approach but emphasizes clarity and efficiency in method chaining. Each method modifies the state of the object and returns the same instance, allowing for seamless chaining of operations.

⚙️

Algorithm

3 steps

1Step 1: Define the Calculator class with an initial result.
2Step 2: Implement methods for each operation that update the result and return 'this'.
3Step 3: Ensure error handling for division by zero.

solution.py28 lines

1class Calculator:
2    def __init__(self, value):
3        self.result = value
4
5    def add(self, value):
6        self.result += value
7        return self
8
9    def subtract(self, value):
10        self.result -= value
11        return self
12
13    def multiply(self, value):
14        self.result *= value
15        return self
16
17    def divide(self, value):
18        if value == 0:
19            raise ValueError('Division by zero is not allowed')
20        self.result /= value
21        return self
22
23    def power(self, value):
24        self.result **= value
25        return self
26
27    def getResult(self):
28        return self.result

ℹ

Complexity note: Each operation is performed in constant time since we are only updating a single variable (result).

1Method chaining allows for cleaner and more readable code.
2Error handling is crucial for operations like division.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.