How do you solve Can Make Arithmetic Progression From Sequence on LeetCode?

Can Make Arithmetic Progression From Sequence (LeetCode #1502) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n log n) time complexity and O(1) space complexity. Key insight: Sorting the array is crucial as any valid arithmetic progression will be in sorted order.

What is the time complexity of Can Make Arithmetic Progression From Sequence?

The optimal solution for Can Make Arithmetic Progression From Sequence runs in O(n log n) time and uses O(1) space. The time complexity is O(n log n) due to sorting the array. The space complexity is O(1) since we are using a constant amount of extra space.

What is the brute force solution for Can Make Arithmetic Progression From Sequence?

The brute force approach for Can Make Arithmetic Progression From Sequence is Brute Force, with O(n!) time complexity and O(n) space complexity. The brute-force approach involves generating all possible permutations of the array and checking if any permutation forms an arithmetic progression. This is straightforward but inefficient due to the factorial growth of permutations. The optimal Optimal Solution approach improves this to O(n log n).

What algorithm or data structure is used to solve Can Make Arithmetic Progression From Sequence?

Can Make Arithmetic Progression From Sequence uses the following concepts: Array, Sorting. The recommended patterns to study are: Sorting, Array.

What are the interview tips for Can Make Arithmetic Progression From Sequence?

Always consider edge cases, like arrays with duplicate values. Explain your thought process clearly while coding; it shows your understanding. Practice identifying patterns in problems, such as recognizing when sorting is beneficial.

What are common mistakes when solving Can Make Arithmetic Progression From Sequence?

Failing to sort the array before checking differences. Not checking all pairs of consecutive elements after sorting.

#1502

Can Make Arithmetic Progression From Sequence

Easy

ArraySortingSortingArray

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n!)	O(n log n)
Space	O(n)	O(1)

💡

Intuition

Time O(n log n)Space O(1)

The optimal solution leverages sorting the array first, then checking the differences between consecutive elements. This is efficient because it reduces the problem to a simple linear scan after sorting.

⚙️

Algorithm

4 steps

1Step 1: Sort the array.
2Step 2: Calculate the common difference using the first two elements.
3Step 3: Iterate through the sorted array and check if the difference between consecutive elements matches the common difference.
4Step 4: If all differences match, return true; otherwise, return false.

solution.py7 lines

1def canMakeArithmeticProgression(arr):
2    arr.sort()
3    diff = arr[1] - arr[0]
4    for i in range(2, len(arr)):
5        if arr[i] - arr[i - 1] != diff:
6            return False
7    return True

ℹ

Complexity note: The time complexity is O(n log n) due to sorting the array. The space complexity is O(1) since we are using a constant amount of extra space.

1Sorting the array is crucial as any valid arithmetic progression will be in sorted order.
2The common difference between consecutive elements must be consistent throughout the array.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.