How do you solve Categorize Box According to Criteria on LeetCode?

Categorize Box According to Criteria (LeetCode #2525) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(1) time complexity and O(1) space complexity. Key insight: Understanding the conditions for categorization is crucial.

What is the time complexity of Categorize Box According to Criteria?

The optimal solution for Categorize Box According to Criteria runs in O(1) time and uses O(1) space. Similar to the brute-force approach, the complexity is O(1) since we perform a constant number of checks.

What is the brute force solution for Categorize Box According to Criteria?

The brute force approach for Categorize Box According to Criteria is Brute Force, with O(1) time complexity and O(1) space complexity. The brute-force approach involves checking each condition for the box's dimensions and mass one by one. This is straightforward and easy to understand, but it may seem repetitive. The optimal Optimal Solution approach improves this to O(1).

What algorithm or data structure is used to solve Categorize Box According to Criteria?

Categorize Box According to Criteria uses the following concepts: Math. The recommended patterns to study are: Conditional Statements, Arithmetic Operations.

What are the interview tips for Categorize Box According to Criteria?

Clearly explain your thought process while coding. Use meaningful variable names to enhance code readability. Test your code with edge cases to ensure robustness.

What are common mistakes when solving Categorize Box According to Criteria?

Overcomplicating the checks by using unnecessary loops. Not considering the order of checks, which can lead to incorrect results.

#2525

Categorize Box According to Criteria

Easy

MathConditional StatementsArithmetic Operations

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(1)	O(1)
Space	O(1)	O(1)

💡

Intuition

Time O(1)Space O(1)

The optimal solution is similar to the brute-force approach but emphasizes clarity and efficiency. We check conditions in a straightforward manner without unnecessary calculations.

⚙️

Algorithm

4 steps

1Step 1: Check if any dimension is greater than or equal to 10^4.
2Step 2: If not, calculate the volume and check if it is greater than or equal to 10^9.
3Step 3: Check if the mass is greater than or equal to 100.
4Step 4: Return the appropriate category based on the results.

solution.py13 lines

1def categorize_box(length, width, height, mass):
2    bulky = length >= 10**4 or width >= 10**4 or height >= 10**4
3    if not bulky:
4        bulky = (length * width * height) >= 10**9
5    heavy = mass >= 100
6    if bulky and heavy:
7        return 'Both'
8    elif bulky:
9        return 'Bulky'
10    elif heavy:
11        return 'Heavy'
12    else:
13        return 'Neither'

ℹ

Complexity note: Similar to the brute-force approach, the complexity is O(1) since we perform a constant number of checks.

1Understanding the conditions for categorization is crucial.
2Calculating volume should be done only if necessary to optimize performance.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.