What is the time complexity of Check if Two Chessboard Squares Have the Same Color?

The optimal solution for Check if Two Chessboard Squares Have the Same Color runs in O(1) time and uses O(1) space. The time complexity remains O(1) as we perform a constant number of operations. The space complexity is also O(1) since no additional space is used.

What is the brute force solution for Check if Two Chessboard Squares Have the Same Color?

The brute force approach for Check if Two Chessboard Squares Have the Same Color is Brute Force, with O(1) time complexity and O(1) space complexity. The brute-force approach checks the color of each square based on its coordinates. Since the chessboard has a predictable pattern, we can determine the color by summing the row and column indices. The optimal Optimal Solution approach improves this to O(1).

What algorithm or data structure is used to solve Check if Two Chessboard Squares Have the Same Color?

Check if Two Chessboard Squares Have the Same Color uses the following concepts: Math, String. The recommended patterns to study are: Mathematical properties (parity checks), String manipulation.

What are the interview tips for Check if Two Chessboard Squares Have the Same Color?

Always clarify the problem statement and constraints before diving into coding. Think about edge cases and how they might affect your solution. Practice explaining your thought process as you code; it helps in interviews.

What are common mistakes when solving Check if Two Chessboard Squares Have the Same Color?

Confusing the column and row indices when calculating colors. Not accounting for the 0-based vs 1-based indexing when converting characters.

#3274

Check if Two Chessboard Squares Have the Same Color

Easy

MathStringMathematical properties (parity checks)String manipulation

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(1)	O(1)
Space	O(1)	O(1)

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Intuition

Time O(1)Space O(1)

The optimal solution uses the same logic as the brute force but is more concise. We can directly compute the color based on the coordinates without needing to store intermediate values.

⚙️

Algorithm

4 steps

1Step 1: Calculate the column index from the character (a-h) as before.
2Step 2: Calculate the row index from the character (1-8) as before.
3Step 3: Directly check if the sum of the column and row indices is even or odd for both coordinates.
4Step 4: Return the comparison result.

solution.py4 lines

1# Full working Python code
2
3def squaresHaveSameColor(coordinate1, coordinate2):
4    return (ord(coordinate1[0]) + int(coordinate1[1])) % 2 == (ord(coordinate2[0]) + int(coordinate2[1])) % 2

ℹ

Complexity note: The time complexity remains O(1) as we perform a constant number of operations. The space complexity is also O(1) since no additional space is used.

1The chessboard colors alternate, which can be determined by the parity of the sum of the row and column indices.
2The problem can be solved in constant time due to the fixed size of the chessboard.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.