How do you solve Compute Decimal Representation on LeetCode?

Compute Decimal Representation (LeetCode #3697) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n) time complexity and O(n) space complexity. Key insight: Each non-zero digit contributes a base-10 component.

What is the time complexity of Compute Decimal Representation?

The optimal solution for Compute Decimal Representation runs in O(n) time and uses O(n) space. The time complexity is linear because we process each digit once, and the space complexity is linear due to storing the components.

What is the brute force solution for Compute Decimal Representation?

The brute force approach for Compute Decimal Representation is Brute Force, with O(n²) time complexity and O(1) space complexity. This approach attempts to break down the number into all possible combinations of base-10 components, which is inefficient. It checks every digit and tries to form components, leading to unnecessary calculations. The optimal Optimal Solution approach improves this to O(n).

What algorithm or data structure is used to solve Compute Decimal Representation?

Compute Decimal Representation uses the following concepts: Array, Math. The recommended patterns to study are: Array, Greedy.

What are the interview tips for Compute Decimal Representation?

Understand the concept of base-10 components clearly. Practice breaking down numbers into their components. Be prepared to explain your thought process clearly.

What are common mistakes when solving Compute Decimal Representation?

Forgetting to check if the digit is zero before adding a component. Not sorting the components in descending order.

#3697

Compute Decimal Representation

Easy

ArrayMathArrayGreedy

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(n)
Space	O(1)	O(n)

💡

Intuition

Time O(n)Space O(n)

This approach directly extracts each digit from the number, calculates its base-10 component, and collects them efficiently in one pass, ensuring minimal operations.

⚙️

Algorithm

3 steps

1Step 1: Initialize an empty list for components and a variable for place value.
2Step 2: Loop through each digit of n, compute its base-10 component if non-zero, and add it to the list.
3Step 3: Return the list sorted in descending order.

solution.py10 lines

1def base10_components(n):
2    components = []
3    place = 1
4    while n > 0:
5        digit = n % 10
6        if digit > 0:
7            components.append(digit * place)
8        n //= 10
9        place *= 10
10    return sorted(components, reverse=True)

ℹ

Complexity note: The time complexity is linear because we process each digit once, and the space complexity is linear due to storing the components.

1Each non-zero digit contributes a base-10 component.
2The place value determines the magnitude of the component.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.