How do you solve Determine if Two Events Have Conflict on LeetCode?

Determine if Two Events Have Conflict (LeetCode #2446) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(1) time complexity and O(1) space complexity. Key insight: Understanding time intervals is crucial for solving overlap problems.

What is the time complexity of Determine if Two Events Have Conflict?

The optimal solution for Determine if Two Events Have Conflict runs in O(1) time and uses O(1) space. This complexity is constant because we perform a fixed number of operations regardless of the input size.

What is the brute force solution for Determine if Two Events Have Conflict?

The brute force approach for Determine if Two Events Have Conflict is Brute Force, with O(n²) time complexity and O(1) space complexity. The brute-force approach checks every possible minute between the start and end times of both events to see if there is any overlap. This is straightforward but inefficient. The optimal Optimal Solution approach improves this to O(1).

What algorithm or data structure is used to solve Determine if Two Events Have Conflict?

Determine if Two Events Have Conflict uses the following concepts: Array, String. The recommended patterns to study are: Hash Map, Array.

What are the interview tips for Determine if Two Events Have Conflict?

Clarify the problem requirements, especially regarding inclusive/exclusive boundaries. Think about edge cases, such as events starting and ending at the same time. Practice converting time formats and working with intervals to build confidence.

What are common mistakes when solving Determine if Two Events Have Conflict?

Failing to account for inclusive boundaries when checking overlaps. Not converting time formats correctly, leading to incorrect comparisons.

#2446

Determine if Two Events Have Conflict

Easy

ArrayStringHash MapArray

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(1)
Space	O(1)	O(1)

💡

Intuition

Time O(1)Space O(1)

Instead of checking each minute, we can directly compare the start and end times of the events. If the events overlap, it can be determined by checking their start and end times.

⚙️

Algorithm

2 steps

1Step 1: Convert the start and end times of both events into minutes since midnight.
2Step 2: Check if the start time of one event is less than or equal to the end time of the other event and vice versa.

solution.py13 lines

1# Full working Python code
2
3def time_to_minutes(time):
4    hours, minutes = map(int, time.split(':'))
5    return hours * 60 + minutes
6
7def have_conflict(event1, event2):
8    start1 = time_to_minutes(event1[0])
9    end1 = time_to_minutes(event1[1])
10    start2 = time_to_minutes(event2[0])
11    end2 = time_to_minutes(event2[1])
12    return start1 <= end2 and start2 <= end1
13

ℹ

Complexity note: This complexity is constant because we perform a fixed number of operations regardless of the input size.

1Understanding time intervals is crucial for solving overlap problems.
2Direct comparisons of start and end times are often more efficient than iterating through every minute.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.