#2535

Difference Between Element Sum and Digit Sum of an Array

Easy
ArrayMathHash MapArray
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Approaches

Brute ForceOptimal
Complexity Comparison
Brute ForceOptimal Solution
Time
O(n²)
O(n)
Space
O(1)
O(1)
💡

Intuition

Time O(n)Space O(1)

The optimal solution calculates both the element sum and digit sum in a single pass through the array, making it more efficient by avoiding nested loops.

⚙️

Algorithm

6 steps
  1. 1Step 1: Initialize two variables, element_sum and digit_sum, to 0.
  2. 2Step 2: Loop through each number in the array.
  3. 3Step 3: For each number, add it directly to element_sum.
  4. 4Step 4: While the number is greater than 0, extract each digit using modulo and integer division, adding each digit to digit_sum.
  5. 5Step 5: Calculate the absolute difference between element_sum and digit_sum.
  6. 6Step 6: Return the absolute difference.
solution.py11 lines
1# Full working Python code
2
3def difference(nums):
4    element_sum = 0
5    digit_sum = 0
6    for num in nums:
7        element_sum += num
8        while num > 0:
9            digit_sum += num % 10
10            num //= 10
11    return abs(element_sum - digit_sum)

Complexity note: The time complexity is O(n) because we only loop through the array once and process each number in constant time. The space complexity is O(1) as we are using a fixed amount of extra space.

  • 1Understanding how to extract digits from numbers is crucial for calculating the digit sum.
  • 2Optimizing the approach to avoid nested loops can significantly improve performance.

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