#2535
Difference Between Element Sum and Digit Sum of an Array
EasyArrayMathHash MapArray
Approaches
Brute ForceOptimal
Complexity Comparison
| Brute Force | Optimal Solution★ | |
|---|---|---|
| Time | O(n²) | O(n) |
| Space | O(1) | O(1) |
💡
Intuition
Time O(n)Space O(1)
The optimal solution calculates both the element sum and digit sum in a single pass through the array, making it more efficient by avoiding nested loops.
⚙️
Algorithm
6 steps- 1Step 1: Initialize two variables, element_sum and digit_sum, to 0.
- 2Step 2: Loop through each number in the array.
- 3Step 3: For each number, add it directly to element_sum.
- 4Step 4: While the number is greater than 0, extract each digit using modulo and integer division, adding each digit to digit_sum.
- 5Step 5: Calculate the absolute difference between element_sum and digit_sum.
- 6Step 6: Return the absolute difference.
solution.py11 lines
1# Full working Python code
2
3def difference(nums):
4 element_sum = 0
5 digit_sum = 0
6 for num in nums:
7 element_sum += num
8 while num > 0:
9 digit_sum += num % 10
10 num //= 10
11 return abs(element_sum - digit_sum)ℹ
Complexity note: The time complexity is O(n) because we only loop through the array once and process each number in constant time. The space complexity is O(1) as we are using a fixed amount of extra space.
- 1Understanding how to extract digits from numbers is crucial for calculating the digit sum.
- 2Optimizing the approach to avoid nested loops can significantly improve performance.
Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.