#1965
Employees With Missing Information
EasyDatabaseHash MapArray
Approaches
Brute ForceOptimal
Complexity Comparison
| Brute Force | Optimal Solution★ | |
|---|---|---|
| Time | O(n²) | O(n) |
| Space | O(1) | O(n) |
💡
Intuition
Time O(n)Space O(n)
In the optimal solution, we will use a single query with LEFT JOIN to efficiently find employees with missing names or salaries. This reduces the need for nested checks and improves performance.
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Algorithm
3 steps- 1Step 1: Perform a LEFT JOIN between Employees and Salaries on employee_id.
- 2Step 2: Select employee_id where name is NULL or salary is NULL.
- 3Step 3: Order the results by employee_id.
solution.py1 lines
1SELECT e.employee_id FROM Employees e LEFT JOIN Salaries s ON e.employee_id = s.employee_id WHERE e.name IS NULL OR s.salary IS NULL ORDER BY e.employee_id;ℹ
Complexity note: The complexity is O(n) because we are scanning through the Employees and Salaries tables once, making it efficient.
- 1Understanding JOIN operations is crucial for efficient database queries.
- 2Recognizing NULL values is key to identifying missing information.
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