How do you solve Find if Digit Game Can Be Won on LeetCode?

Find if Digit Game Can Be Won (LeetCode #3232) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n) time complexity and O(1) space complexity. Key insight: Alice's winning condition is based on the sums of single and double-digit numbers.

What is the brute force solution for Find if Digit Game Can Be Won?

The brute force approach for Find if Digit Game Can Be Won is Brute Force, with O(n) time complexity and O(1) space complexity. In the brute force approach, we will calculate the sum of single-digit and double-digit numbers separately. Then, we will compare the sums to see if Alice can win. This method is straightforward but not efficient. The optimal Optimal Solution approach improves this to O(n).

What algorithm or data structure is used to solve Find if Digit Game Can Be Won?

Find if Digit Game Can Be Won uses the following concepts: Array, Math. The recommended patterns to study are: Array, Math.

What are the interview tips for Find if Digit Game Can Be Won?

Always clarify the problem statement and constraints before jumping into coding. Think aloud while solving the problem to show your thought process. Consider edge cases and how they might affect your solution.

What are common mistakes when solving Find if Digit Game Can Be Won?

Not considering edge cases where all numbers are single or double digits. Failing to correctly calculate Bob's sum based on the chosen numbers.

#3232

Find if Digit Game Can Be Won

Easy

ArrayMathArrayMath

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n)	O(n)
Space	O(1)	O(1)

💡

Intuition

Time O(n)Space O(1)

The optimal solution is similar to the brute force approach but focuses on calculating the sums in a single pass and directly comparing them. This avoids unnecessary calculations and is efficient.

⚙️

Algorithm

5 steps

1Step 1: Initialize sum_single and sum_double to 0.
2Step 2: Traverse the nums array once to calculate both sums.
3Step 3: Calculate total_sum as the sum of all elements in nums.
4Step 4: Calculate Bob's sum as total_sum - max(sum_single, sum_double).
5Step 5: Return true if sum_single > Bob's sum or sum_double > Bob's sum, otherwise return false.

solution.py11 lines

1def canAliceWin(nums):
2    sum_single = 0
3    sum_double = 0
4    for num in nums:
5        if num < 10:
6            sum_single += num
7        else:
8            sum_double += num
9    total_sum = sum_single + sum_double
10    bob_sum = total_sum - max(sum_single, sum_double)
11    return sum_single > bob_sum or sum_double > bob_sum

ℹ

Complexity note: The time complexity is O(n) because we only traverse the array once. The space complexity is O(1) since we only use a few extra variables for sums.

1Alice's winning condition is based on the sums of single and double-digit numbers.
2If Alice's sum of chosen numbers is greater than Bob's remaining numbers, she wins.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.