How do you solve Find Most Frequent Vowel and Consonant on LeetCode?

Find Most Frequent Vowel and Consonant (LeetCode #3541) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n) time complexity and O(n) space complexity. Key insight: Vowels and consonants can be counted separately.

What is the time complexity of Find Most Frequent Vowel and Consonant?

The optimal solution for Find Most Frequent Vowel and Consonant runs in O(n) time and uses O(n) space. The algorithm processes the string in a single pass, leading to O(n) complexity.

What is the brute force solution for Find Most Frequent Vowel and Consonant?

The brute force approach for Find Most Frequent Vowel and Consonant is Brute Force, with O(n²) time complexity and O(1) space complexity. Count frequencies of each character, then separately find the max for vowels and consonants. This is straightforward but inefficient. The optimal Optimal Solution approach improves this to O(n).

What algorithm or data structure is used to solve Find Most Frequent Vowel and Consonant?

Find Most Frequent Vowel and Consonant uses the following concepts: Hash Table, String, Counting. The recommended patterns to study are: Hash Map, Array.

What are the interview tips for Find Most Frequent Vowel and Consonant?

Explain your thought process clearly. Discuss edge cases upfront. Be prepared to optimize your solution.

What are common mistakes when solving Find Most Frequent Vowel and Consonant?

Not handling empty strings properly. Confusing vowel and consonant indices.

#3541

Find Most Frequent Vowel and Consonant

Easy

Hash TableStringCountingHash MapArray

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(n)
Space	O(1)	O(n)

💡

Intuition

Time O(n)Space O(n)

Use a single pass to count frequencies in a hash map, allowing efficient retrieval of max frequencies.

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Algorithm

3 steps

1Step 1: Initialize a frequency map for vowels and consonants.
2Step 2: Traverse the string once, updating the frequency map based on character type.
3Step 3: Calculate the maximum frequency for vowels and consonants and return their sum.

solution.py10 lines

1def most_frequent(s):
2    freq = {'vowels': {}, 'consonants': {}}
3    for char in s:
4        if char in 'aeiou':
5            freq['vowels'][char] = freq['vowels'].get(char, 0) + 1
6        else:
7            freq['consonants'][char] = freq['consonants'].get(char, 0) + 1
8    max_vowel = max(freq['vowels'].values(), default=0)
9    max_consonant = max(freq['consonants'].values(), default=0)
10    return max_vowel + max_consonant

ℹ

Complexity note: The algorithm processes the string in a single pass, leading to O(n) complexity.

1Vowels and consonants can be counted separately.
2Using a hash map allows for efficient frequency counting.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.