#2099
Find Subsequence of Length K With the Largest Sum
EasyArrayHash TableSortingHeap (Priority Queue)SortingGreedy Algorithms
Approaches
Brute ForceOptimal
Complexity Comparison
| Brute Force | Optimal Solution★ | |
|---|---|---|
| Time | O(n²) | O(n log n) |
| Space | O(1) | O(n) |
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Intuition
Time O(n log n)Space O(n)
To find the largest sum subsequence of length k, we can sort the array and select the largest k elements. This is efficient because we are directly targeting the elements that contribute to the maximum sum.
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Algorithm
3 steps- 1Step 1: Sort the array while keeping track of the original indices.
- 2Step 2: Select the largest k elements from the sorted array.
- 3Step 3: Sort the selected elements based on their original indices to maintain the subsequence order.
solution.py6 lines
1def max_sum_subsequence(nums, k):
2 indexed_nums = list(enumerate(nums))
3 indexed_nums.sort(key=lambda x: x[1], reverse=True)
4 top_k = indexed_nums[:k]
5 top_k.sort(key=lambda x: x[0])
6 return [num for index, num in top_k]ℹ
Complexity note: The sorting step dominates the time complexity, making it O(n log n). The space complexity is O(n) due to storing the indexed elements.
- 1Sorting the array helps in efficiently finding the largest elements.
- 2Maintaining the original indices is crucial to ensure the subsequence order.
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