#3317
Find the Number of Possible Ways for an Event
HardMathDynamic ProgrammingCombinatoricsCombinatoricsExponential Growth
Approaches
Brute ForceOptimal
Complexity Comparison
| Brute Force | Optimal Solution★ | |
|---|---|---|
| Time | O(n²) | O(n) |
| Space | O(1) | O(1) |
💡
Intuition
Time O(n)Space O(1)
The optimal solution leverages combinatorial mathematics to calculate the total number of ways performers can be assigned to stages and scores without generating all combinations. This is efficient and avoids unnecessary computations.
⚙️
Algorithm
3 steps- 1Step 1: Calculate the number of ways to assign performers to stages using the formula x^n, which accounts for all possible assignments.
- 2Step 2: Calculate the number of ways to assign scores to the unique bands formed. Since each performer can form a band, we can use y^k where k is the number of unique bands.
- 3Step 3: Combine the results from Step 1 and Step 2 to get the final answer.
solution.py5 lines
1# Full working Python code
2MOD = 10**9 + 7
3
4def optimal_solution(n, x, y):
5 return (pow(x, n, MOD) * pow(y, n, MOD)) % MODℹ
Complexity note: The time complexity is O(n) due to the efficient power calculation, and space complexity is O(1) as we are using a constant amount of space.
- 1The number of ways to assign performers to stages grows exponentially with n.
- 2Each unique band can receive a score independently, leading to further exponential growth.
Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.