#2833
Furthest Point From Origin
EasyStringCountingCountingGreedy
Approaches
Brute ForceOptimal
Complexity Comparison
| Brute Force | Optimal Solution★ | |
|---|---|---|
| Time | O(n²) | O(n) |
| Space | O(2^n) | O(1) |
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Intuition
Time O(n)Space O(1)
Instead of generating all combinations, we can directly calculate the furthest distance by counting the occurrences of 'L', 'R', and '_' in the string. We replace all '_' with the character that occurs the most to maximize the distance.
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Algorithm
3 steps- 1Step 1: Count the occurrences of 'L', 'R', and '_' in the string.
- 2Step 2: Determine the maximum distance by replacing all '_' with the character that occurs the most.
- 3Step 3: Calculate the final distance from the origin.
solution.py6 lines
1def furthestDistance(moves):
2 count_L = moves.count('L')
3 count_R = moves.count('R')
4 count_Underscore = moves.count('_')
5 max_distance = abs(count_L - (count_R + count_Underscore))
6 return max_distanceℹ
Complexity note: The time complexity is O(n) because we traverse the string once to count the characters. The space complexity is O(1) since we only use a fixed amount of extra space for counters.
- 1Replacing '_' with the most frequent character maximizes distance.
- 2Count-based approach is more efficient than generating combinations.
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