How do you solve Generate Schedule on LeetCode?

Generate Schedule (LeetCode #3680) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n²) time complexity and O(n) space complexity. Key insight: A round-robin approach ensures all teams play without consecutive matches.

What is the time complexity of Generate Schedule?

The optimal solution for Generate Schedule runs in O(n²) time and uses O(n) space. The algorithm runs in quadratic time due to nested loops but uses linear space to store the schedule.

What is the brute force solution for Generate Schedule?

The brute force approach for Generate Schedule is Brute Force, with O(n²) time complexity and O(1) space complexity. Generate all possible match pairings and check for consecutive days. This approach is inefficient as it doesn't scale well with larger n. The optimal Optimal Solution approach improves this to O(n²).

What algorithm or data structure is used to solve Generate Schedule?

Generate Schedule uses the following concepts: Array, Math, Greedy. The recommended patterns to study are: Hash Map, Array.

What are the interview tips for Generate Schedule?

Clarify the problem constraints before diving into coding. Think about edge cases and how they affect your solution. Explain your thought process clearly while coding.

What are common mistakes when solving Generate Schedule?

Forgetting to check for consecutive matches. Not handling edge cases like n < 3.

#3680

Generate Schedule

Medium

ArrayMathGreedyHash MapArray

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(n²)
Space	O(1)	O(n)

💡

Intuition

Time O(n²)Space O(n)

Use a round-robin scheduling method to ensure no team plays on consecutive days while covering all matches efficiently.

⚙️

Algorithm

3 steps

1Step 1: Create a list to hold the matches.
2Step 2: Loop through each team and schedule matches while skipping the previous day's teams.
3Step 3: Return the constructed schedule.

solution.py11 lines

1def generate_schedule(n):
2    if n < 3:
3        return []
4    schedule = []
5    for i in range(n):
6        for j in range(1, n):
7            home = (i + j) % n
8            away = (i + n - j) % n
9            if home != away:
10                schedule.append([home, away])
11    return schedule

ℹ

Complexity note: The algorithm runs in quadratic time due to nested loops but uses linear space to store the schedule.

1A round-robin approach ensures all teams play without consecutive matches.
2The problem is infeasible for n < 3 due to the requirement of home and away games.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.