How do you solve Incremental Memory Leak on LeetCode?

Incremental Memory Leak (LeetCode #1860) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n) time complexity and O(1) space complexity. Key insight: Memory allocation is based on the available memory of each stick.

What is the brute force solution for Incremental Memory Leak?

The brute force approach for Incremental Memory Leak is Brute Force, with O(n²) time complexity and O(1) space complexity. We can simulate the memory allocation process second by second, checking which memory stick has more available memory and allocating the required bits. This approach is straightforward but can be inefficient as it may require many iterations. The optimal Optimal Solution approach improves this to O(n).

What algorithm or data structure is used to solve Incremental Memory Leak?

Incremental Memory Leak uses the following concepts: Math, Simulation. The recommended patterns to study are: Simulation, Greedy.

What are the interview tips for Incremental Memory Leak?

Always clarify the problem statement and constraints. Think aloud while solving to show your thought process. Consider edge cases, such as when both memory sticks start with zero.

What are common mistakes when solving Incremental Memory Leak?

Not correctly checking which memory stick has more available memory. Failing to update the memory after allocation.

#1860

Incremental Memory Leak

Medium

MathSimulationSimulationGreedy

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(n)
Space	O(1)	O(1)

💡

Intuition

Time O(n)Space O(1)

Instead of simulating each second, we can calculate the maximum time until the program crashes based on the available memory. This allows us to find the crash time directly without iterating through every second.

⚙️

Algorithm

3 steps

1Step 1: Determine the total memory available and the maximum time it can run before crashing.
2Step 2: Use a loop to allocate memory until we reach the point where neither stick can allocate the required bits.
3Step 3: Calculate the remaining memory after the last successful allocation to determine the crash time.

solution.py14 lines

1def incremental_memory_leak(memory1, memory2):
2    time = 0
3    while True:
4        time += 1
5        if memory1 >= memory2:
6            if memory1 < time:
7                return [time, memory1, memory2]
8            memory1 -= time
9        else:
10            if memory2 < time:
11                return [time, memory1, memory2]
12            memory2 -= time
13
14print(incremental_memory_leak(8, 11))

ℹ

Complexity note: The time complexity is O(n) because we only iterate through the seconds until we find the crash point, which is linear with respect to the number of seconds.

1Memory allocation is based on the available memory of each stick.
2The program crashes when neither stick can allocate the required bits.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.