How do you solve Largest Merge Of Two Strings on LeetCode?

Largest Merge Of Two Strings (LeetCode #1754) can be solved using Brute Force. The optimal approach is Brute Force with O(n²) time complexity and O(1) space complexity. Key insight: The brute force approach involves generating all possible merges of the two strings and selecting the largest one. This is straightforward but inefficient, as it checks every combination.

What algorithm or data structure is used to solve Largest Merge Of Two Strings?

Largest Merge Of Two Strings uses the following concepts: Two Pointers, String, Greedy. The recommended patterns to study are: .

Largest Merge Of Two Strings — LeetCode #1754 (Medium)

Tags: Two Pointers, String, Greedy

Related patterns:

Brute Force approach

Time complexity: O(n²). Space complexity: O(1).

The brute force approach involves generating all possible merges of the two strings and selecting the largest one. This is straightforward but inefficient, as it checks every combination.

The time complexity is O(n²) because in the worst case, we compare the strings word1 and word2 at each step, leading to a quadratic number of comparisons.

Step 1: Initialize an empty string 'merge'.
Step 2: While either word1 or word2 is non-empty, compare the first characters of both strings.
Step 3: Append the larger character to 'merge' and remove it from the respective string.

1. Initial: word1 = 'cabaa', word2 = 'bcaaa', merge = '' 2. Compare: 'cabaa' > 'bcaaa' → merge = 'c', word1 = 'abaa', word2 = 'bcaaa' 3. Compare: 'abaa' < 'bcaaa' → merge = 'cb', word1 = 'abaa', word2 = 'caaa' 4. Compare: 'abaa' < 'caaa' → merge = 'cbc', word1 = 'abaa', word2 = 'aaa' 5. Compare: 'abaa' > 'aaa' → merge = 'cbca', word1 = 'baa', word2 = 'aaa' 6. Continue until both strings are empty → merge = 'cbcabaaaaa'

#1754

Largest Merge Of Two Strings

Medium

Two Pointers↗String↗Greedy↗

LeetCode ↗

Approaches

💡

Intuition

Time O(n²)Space O(1)

The brute force approach involves generating all possible merges of the two strings and selecting the largest one. This is straightforward but inefficient, as it checks every combination.

⚙️

Algorithm

3 steps

1Step 1: Initialize an empty string 'merge'.
2Step 2: While either word1 or word2 is non-empty, compare the first characters of both strings.
3Step 3: Append the larger character to 'merge' and remove it from the respective string.

solution.py10 lines

1def largestMerge(word1, word2):
2    merge = ''
3    while word1 or word2:
4        if word1 > word2:
5            merge += word1[0]
6            word1 = word1[1:]
7        else:
8            merge += word2[0]
9            word2 = word2[1:]
10    return merge

ℹ

Complexity note: The time complexity is O(n²) because in the worst case, we compare the strings word1 and word2 at each step, leading to a quadratic number of comparisons.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.