#1147

Longest Chunked Palindrome Decomposition

Hard
Two PointersStringDynamic ProgrammingGreedyRolling HashHash FunctionDynamic ProgrammingTwo Pointers
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Approaches

Brute ForceOptimal
Complexity Comparison
Brute ForceOptimal Solution
Time
O(n²)
O(n²)
Space
O(1)
O(n)
💡

Intuition

Time O(n²)Space O(n)

The optimal solution uses a dynamic programming approach to efficiently find the longest chunked palindrome decomposition. By leveraging previously computed results, we can avoid redundant checks and improve performance.

⚙️

Algorithm

3 steps
  1. 1Step 1: Initialize a DP array where dp[i] represents the maximum k for the substring text[0:i].
  2. 2Step 2: Iterate through the string and for each position, check for possible palindromic chunks.
  3. 3Step 3: Update the DP array based on valid splits found.
solution.py11 lines
1def longestChunkedPalindromeDecomposition(text):
2    n = len(text)
3    dp = [0] * (n + 1)
4    dp[0] = 1
5    for i in range(1, n + 1):
6        for j in range(i):
7            left = text[j:i]
8            right = text[n - (i - j):n - j]
9            if left == right:
10                dp[i] = max(dp[i], dp[j] + 1)
11    return dp[n]

Complexity note: The time complexity remains O(n²) due to the nested loops, but we use a DP array to store results, which improves efficiency by avoiding redundant calculations.

  • 1Understanding the palindrome structure is crucial for splitting the string correctly.
  • 2Dynamic programming can significantly reduce redundant checks by storing intermediate results.

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