#1147
Longest Chunked Palindrome Decomposition
HardTwo PointersStringDynamic ProgrammingGreedyRolling HashHash FunctionDynamic ProgrammingTwo Pointers
Approaches
Brute ForceOptimal
Complexity Comparison
| Brute Force | Optimal Solution★ | |
|---|---|---|
| Time | O(n²) | O(n²) |
| Space | O(1) | O(n) |
💡
Intuition
Time O(n²)Space O(n)
The optimal solution uses a dynamic programming approach to efficiently find the longest chunked palindrome decomposition. By leveraging previously computed results, we can avoid redundant checks and improve performance.
⚙️
Algorithm
3 steps- 1Step 1: Initialize a DP array where dp[i] represents the maximum k for the substring text[0:i].
- 2Step 2: Iterate through the string and for each position, check for possible palindromic chunks.
- 3Step 3: Update the DP array based on valid splits found.
solution.py11 lines
1def longestChunkedPalindromeDecomposition(text):
2 n = len(text)
3 dp = [0] * (n + 1)
4 dp[0] = 1
5 for i in range(1, n + 1):
6 for j in range(i):
7 left = text[j:i]
8 right = text[n - (i - j):n - j]
9 if left == right:
10 dp[i] = max(dp[i], dp[j] + 1)
11 return dp[n]ℹ
Complexity note: The time complexity remains O(n²) due to the nested loops, but we use a DP array to store results, which improves efficiency by avoiding redundant calculations.
- 1Understanding the palindrome structure is crucial for splitting the string correctly.
- 2Dynamic programming can significantly reduce redundant checks by storing intermediate results.
Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.