How do you solve Maximum Number of Consecutive Values You Can Make on LeetCode?

Maximum Number of Consecutive Values You Can Make (LeetCode #1798) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n log n) time complexity and O(1) space complexity. Key insight: If you can make all values up to x, and you have a coin of value v, you can make all values up to x + v.

What is the time complexity of Maximum Number of Consecutive Values You Can Make?

The optimal solution for Maximum Number of Consecutive Values You Can Make runs in O(n log n) time and uses O(1) space. The time complexity is O(n log n) due to the sorting step, while the space complexity is O(1) since we are using a constant amount of extra space.

What is the brute force solution for Maximum Number of Consecutive Values You Can Make?

The brute force approach for Maximum Number of Consecutive Values You Can Make is Brute Force, with O(n²) time complexity and O(1) space complexity. The brute force approach involves generating all possible sums using the coins and checking how many consecutive values can be formed starting from 0. This method is straightforward but inefficient. The optimal Optimal Solution approach improves this to O(n log n).

What algorithm or data structure is used to solve Maximum Number of Consecutive Values You Can Make?

Maximum Number of Consecutive Values You Can Make uses the following concepts: Array, Greedy, Sorting. The recommended patterns to study are: Greedy, Sorting.

What are the interview tips for Maximum Number of Consecutive Values You Can Make?

Always start with a brute-force solution to understand the problem better. Think about how sorting can simplify the problem. Practice explaining your thought process clearly, as communication is key in interviews.

What are common mistakes when solving Maximum Number of Consecutive Values You Can Make?

Failing to sort the coins before processing them. Not considering the case where a coin is larger than the current max consecutive value + 1, which indicates a gap.

#1798

Maximum Number of Consecutive Values You Can Make

Medium

ArrayGreedySortingGreedySorting

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(n log n)
Space	O(1)	O(1)

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Intuition

Time O(n log n)Space O(1)

The optimal approach involves sorting the coins and using a greedy strategy to find the maximum consecutive values. If we can make all values up to x and have a coin of value v, we can then make all values up to x + v.

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Algorithm

5 steps

1Step 1: Sort the coins array.
2Step 2: Initialize a variable 'maxConsecutive' to 0.
3Step 3: Iterate through the sorted coins. For each coin, if it is greater than 'maxConsecutive + 1', break the loop.
4Step 4: Otherwise, add the coin value to 'maxConsecutive'.
5Step 5: Return 'maxConsecutive' + 1 as the result.

solution.py10 lines

1# Full working Python code
2
3def maxConsecutiveValues(coins):
4    coins.sort()
5    maxConsecutive = 0
6    for coin in coins:
7        if coin > maxConsecutive + 1:
8            break
9        maxConsecutive += coin
10    return maxConsecutive + 1

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Complexity note: The time complexity is O(n log n) due to the sorting step, while the space complexity is O(1) since we are using a constant amount of extra space.

1If you can make all values up to x, and you have a coin of value v, you can make all values up to x + v.
2Sorting the coins allows us to efficiently determine the maximum consecutive values we can create.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.