How do you solve Maximum Number of Words Found in Sentences on LeetCode?

Maximum Number of Words Found in Sentences (LeetCode #2114) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n) time complexity and O(1) space complexity. Key insight: Counting spaces gives a direct way to determine the number of words.

What is the time complexity of Maximum Number of Words Found in Sentences?

The optimal solution for Maximum Number of Words Found in Sentences runs in O(n) time and uses O(1) space. The time complexity is O(n) because we are processing each sentence once, and the space complexity is O(1) since we only use a few variables.

What is the brute force solution for Maximum Number of Words Found in Sentences?

The brute force approach for Maximum Number of Words Found in Sentences is Brute Force, with O(n²) time complexity and O(1) space complexity. The brute force approach involves counting the number of words in each sentence by splitting the sentence into words and then finding the maximum count. This is straightforward but can be inefficient for larger inputs. The optimal Optimal Solution approach improves this to O(n).

What algorithm or data structure is used to solve Maximum Number of Words Found in Sentences?

Maximum Number of Words Found in Sentences uses the following concepts: Array, String. The recommended patterns to study are: String Manipulation, Array Traversal.

What are the interview tips for Maximum Number of Words Found in Sentences?

Always clarify the problem requirements before coding. Think about edge cases and how your solution handles them. Practice writing clean and efficient code.

What are common mistakes when solving Maximum Number of Words Found in Sentences?

Not considering edge cases like sentences with only one word. Overcomplicating the counting logic by using unnecessary data structures.

#2114

Maximum Number of Words Found in Sentences

Easy

ArrayStringString ManipulationArray Traversal

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(n)
Space	O(1)	O(1)

💡

Intuition

Time O(n)Space O(1)

The optimal solution leverages a single pass through the sentences to count words, which is more efficient than repeatedly splitting strings. This reduces unnecessary computations and improves performance.

⚙️

Algorithm

4 steps

1Step 1: Initialize a variable to keep track of the maximum word count.
2Step 2: Loop through each sentence in the sentences array.
3Step 3: Count the number of spaces in the sentence, which gives the number of words as spaces + 1.
4Step 4: Update the maximum word count if the current count is greater than the maximum.

solution.py8 lines

1# Full working Python code
2
3def maxWords(sentences):
4    max_count = 0
5    for sentence in sentences:
6        word_count = sentence.count(' ') + 1
7        max_count = max(max_count, word_count)
8    return max_count

ℹ

Complexity note: The time complexity is O(n) because we are processing each sentence once, and the space complexity is O(1) since we only use a few variables.

1Counting spaces gives a direct way to determine the number of words.
2Using string manipulation functions can simplify the counting process.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.