How do you solve Maximum Product of Two Digits on LeetCode?

Maximum Product of Two Digits (LeetCode #3536) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n) time complexity and O(1) space complexity. Key insight: The maximum product comes from the two largest digits.

What is the time complexity of Maximum Product of Two Digits?

The optimal solution for Maximum Product of Two Digits runs in O(n) time and uses O(1) space. The complexity is O(n) because we only traverse the digits once to find the two largest.

What is the brute force solution for Maximum Product of Two Digits?

The brute force approach for Maximum Product of Two Digits is Brute Force, with O(n²) time complexity and O(1) space complexity. We can find the maximum product by checking all pairs of digits in the number. This approach is straightforward but inefficient for larger inputs. The optimal Optimal Solution approach improves this to O(n).

What algorithm or data structure is used to solve Maximum Product of Two Digits?

Maximum Product of Two Digits uses the following concepts: Math, Sorting. The recommended patterns to study are: Array, Sorting.

What are the interview tips for Maximum Product of Two Digits?

Explain your thought process clearly. Discuss time and space complexity. Consider edge cases and constraints.

What are common mistakes when solving Maximum Product of Two Digits?

Not considering the same digit can be used twice. Forgetting to handle cases where digits are the same.

#3536

Maximum Product of Two Digits

Easy

MathSortingArraySorting

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(n)
Space	O(1)	O(1)

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Intuition

Time O(n)Space O(1)

Instead of checking all pairs, we can find the two largest digits and multiply them for the maximum product. This is efficient and quick.

⚙️

Algorithm

3 steps

1Step 1: Convert the integer n to a list of its digits.
2Step 2: Identify the two largest digits in the list.
3Step 3: Return the product of these two digits.

solution.py3 lines

1def maxProduct(n):
2    digits = sorted([int(d) for d in str(n)])
3    return digits[-1] * digits[-2]

ℹ

Complexity note: The complexity is O(n) because we only traverse the digits once to find the two largest.

1The maximum product comes from the two largest digits.
2Sorting can help quickly identify the largest elements.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.