How do you solve Maximum Walls Destroyed by Robots on LeetCode?

Maximum Walls Destroyed by Robots (LeetCode #3661) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n log n) time complexity and O(n) space complexity. Key insight: Sorting helps in efficiently checking ranges.

What is the time complexity of Maximum Walls Destroyed by Robots?

The optimal solution for Maximum Walls Destroyed by Robots runs in O(n log n) time and uses O(n) space. Sorting takes O(n log n), and checking walls takes O(n) for each robot.

What is the brute force solution for Maximum Walls Destroyed by Robots?

The brute force approach for Maximum Walls Destroyed by Robots is Brute Force, with O(n²) time complexity and O(1) space complexity. Check each robot's firing range against every wall. This method is straightforward but inefficient as it checks all combinations. The optimal Optimal Solution approach improves this to O(n log n).

What algorithm or data structure is used to solve Maximum Walls Destroyed by Robots?

Maximum Walls Destroyed by Robots uses the following concepts: Array, Binary Search, Dynamic Programming, Sorting. The recommended patterns to study are: Hash Map, Array.

What are the interview tips for Maximum Walls Destroyed by Robots?

Clarify the problem constraints. Discuss edge cases like overlapping positions. Explain your thought process while coding.

What are common mistakes when solving Maximum Walls Destroyed by Robots?

Not considering walls at robot positions. Ignoring the effect of neighboring robots.

#3661

Maximum Walls Destroyed by Robots

Hard

ArrayBinary SearchDynamic ProgrammingSortingHash MapArray

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(n log n)
Space	O(1)	O(n)

💡

Intuition

Time O(n log n)Space O(n)

Sort robots and walls, then use binary search to efficiently find the range of walls affected by each robot.

⚙️

Algorithm

3 steps

1Step 1: Sort robots and walls arrays.
2Step 2: For each robot, calculate the effective range and use binary search to find walls within that range.
3Step 3: Use a set to count unique walls destroyed.

solution.py14 lines

1def maxWallsDestroyed(robots, distance, walls):
2    robots.sort()
3    walls.sort()
4    destroyed = set()
5    for i in range(len(robots)):
6        left = robots[i] - distance[i]
7        right = robots[i] + distance[i]
8        for wall in walls:
9            if wall < left:
10                continue
11            if wall > right:
12                break
13            destroyed.add(wall)
14    return len(destroyed)

ℹ

Complexity note: Sorting takes O(n log n), and checking walls takes O(n) for each robot.

1Sorting helps in efficiently checking ranges.
2Using sets avoids counting duplicates.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.