How do you solve Minimum Length of Anagram Concatenation on LeetCode?

Minimum Length of Anagram Concatenation (LeetCode #3138) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n) time complexity and O(1) space complexity. Key insight: The minimum length of t must be a divisor of the length of s.

What is the time complexity of Minimum Length of Anagram Concatenation?

The optimal solution for Minimum Length of Anagram Concatenation runs in O(n) time and uses O(1) space. The time complexity is O(n) because we only traverse the string a couple of times to count frequencies and find the maximum frequency.

What is the brute force solution for Minimum Length of Anagram Concatenation?

The brute force approach for Minimum Length of Anagram Concatenation is Brute Force, with O(n²) time complexity and O(1) space complexity. The brute force approach involves checking every possible length of substring that could represent the string t. We will check if the string s can be formed by concatenating anagrams of this substring. The optimal Optimal Solution approach improves this to O(n).

What algorithm or data structure is used to solve Minimum Length of Anagram Concatenation?

Minimum Length of Anagram Concatenation uses the following concepts: Hash Table, String, Counting. The recommended patterns to study are: Hash Map, Array.

What are the interview tips for Minimum Length of Anagram Concatenation?

Always think about the constraints and properties of the problem, such as divisors. Explain your thought process clearly during the interview. Test your solution with edge cases before finalizing it.

What are common mistakes when solving Minimum Length of Anagram Concatenation?

Not considering all divisors of the string length in the brute force approach. Overlooking the need to count character frequencies accurately.

#3138

Minimum Length of Anagram Concatenation

Medium

Hash TableStringCountingHash MapArray

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(n)
Space	O(1)	O(1)

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Intuition

Time O(n)Space O(1)

The optimal approach leverages the frequency of characters in the string s. We can determine the minimum length of t by finding the maximum frequency of any character and dividing the total length of s by this frequency.

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Algorithm

3 steps

1Step 1: Count the frequency of each character in the string s.
2Step 2: Find the maximum frequency among these counts.
3Step 3: The minimum length of t is the total length of s divided by this maximum frequency.

solution.py8 lines

1# Full working Python code
2
3def min_length_anagram(s):
4    from collections import Counter
5    count = Counter(s)
6    max_freq = max(count.values())
7    return len(s) // max_freq
8

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Complexity note: The time complexity is O(n) because we only traverse the string a couple of times to count frequencies and find the maximum frequency.

1The minimum length of t must be a divisor of the length of s.
2The maximum frequency of any character directly determines the minimum length of t.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.