How do you solve Minimum Operations to Exceed Threshold Value I on LeetCode?

Minimum Operations to Exceed Threshold Value I (LeetCode #3065) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n) time complexity and O(1) space complexity. Key insight: Sorting the array can help in understanding the problem but is not necessary for counting operations.

What is the time complexity of Minimum Operations to Exceed Threshold Value I?

The optimal solution for Minimum Operations to Exceed Threshold Value I runs in O(n) time and uses O(1) space. This approach is O(n) because we simply iterate through the array once. The space complexity is O(1) since we only use a counter.

What is the brute force solution for Minimum Operations to Exceed Threshold Value I?

The brute force approach for Minimum Operations to Exceed Threshold Value I is Brute Force, with O(n log n) time complexity and O(1) space complexity. The brute force approach involves repeatedly removing the smallest element from the array until all remaining elements are greater than or equal to k. This is straightforward but inefficient. The optimal Optimal Solution approach improves this to O(n).

What algorithm or data structure is used to solve Minimum Operations to Exceed Threshold Value I?

Minimum Operations to Exceed Threshold Value I uses the following concepts: Array. The recommended patterns to study are: Array, Counting.

What are the interview tips for Minimum Operations to Exceed Threshold Value I?

Always consider the simplest approach first; it can help clarify your understanding of the problem. Be mindful of edge cases, such as when all elements are already >= k. Communicate your thought process clearly during the interview; explaining your reasoning can earn you points even if your solution is not optimal.

What are common mistakes when solving Minimum Operations to Exceed Threshold Value I?

Students often forget to handle the case where no operations are needed, leading to incorrect outputs. Overcomplicating the solution by trying to sort or manipulate the array unnecessarily.

#3065

Minimum Operations to Exceed Threshold Value I

Easy

ArrayArrayCounting

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n log n)	O(n)
Space	O(1)	O(1)

💡

Intuition

Time O(n)Space O(1)

The optimal approach counts the number of elements that are less than k directly without sorting, which is more efficient.

⚙️

Algorithm

4 steps

1Step 1: Initialize a counter for operations to zero.
2Step 2: Iterate through the array and for each element, check if it is less than k.
3Step 3: If it is less, increment the operations counter.
4Step 4: Return the operations counter as the result.

solution.py3 lines

1def min_operations(nums, k):
2    operations = sum(1 for num in nums if num < k)
3    return operations

ℹ

Complexity note: This approach is O(n) because we simply iterate through the array once. The space complexity is O(1) since we only use a counter.

1Sorting the array can help in understanding the problem but is not necessary for counting operations.
2Directly counting elements less than k is more efficient and leads to the optimal solution.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.