How do you solve Minimum Operations to Make Binary Palindrome on LeetCode?

Minimum Operations to Make Binary Palindrome (LeetCode #3766) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n) time complexity and O(n) space complexity. Key insight: Binary representation is crucial for palindrome checks.

What is the time complexity of Minimum Operations to Make Binary Palindrome?

The optimal solution for Minimum Operations to Make Binary Palindrome runs in O(n) time and uses O(n) space. Precomputing palindromes takes linear time, and searching them is efficient due to the reduced size.

What is the brute force solution for Minimum Operations to Make Binary Palindrome?

The brute force approach for Minimum Operations to Make Binary Palindrome is Brute Force, with O(n²) time complexity and O(1) space complexity. Check every possible number around nums[i] to find the nearest binary palindrome. This involves incrementing and decrementing until a palindrome is found. The optimal Optimal Solution approach improves this to O(n).

What algorithm or data structure is used to solve Minimum Operations to Make Binary Palindrome?

Minimum Operations to Make Binary Palindrome uses the following concepts: Array, Two Pointers, Binary Search, Bit Manipulation. The recommended patterns to study are: Hash Map, Array.

What are the interview tips for Minimum Operations to Make Binary Palindrome?

Explain your thought process clearly. Discuss trade-offs between brute force and optimized approaches. Practice similar problems to build confidence.

What are common mistakes when solving Minimum Operations to Make Binary Palindrome?

Not considering edge cases like 0 or very large numbers. Overlooking the efficiency of binary search in the optimal solution.

#3766

Minimum Operations to Make Binary Palindrome

Medium

ArrayTwo PointersBinary SearchBit ManipulationHash MapArray

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(n)
Space	O(1)	O(n)

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Intuition

Time O(n)Space O(n)

Precompute binary palindromes and find the closest one for each number using binary search. This reduces the search space significantly.

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Algorithm

3 steps

1Step 1: Precompute binary palindromes up to a reasonable limit.
2Step 2: For each number in nums, use binary search to find the closest binary palindrome.
3Step 3: Calculate the difference and store the result.

solution.py2 lines

1def generate_palindromes(limit): return [i for i in range(limit) if bin(i)[2:] == bin(i)[2:][::-1]]
2def min_operations(nums): palindromes = generate_palindromes(10000); return [min(abs(n - p) for p in palindromes) for n in nums]

ℹ

Complexity note: Precomputing palindromes takes linear time, and searching them is efficient due to the reduced size.

1Binary representation is crucial for palindrome checks.
2Precomputation of palindromes reduces repeated calculations.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.