How do you solve Most Visited Sector in a Circular Track on LeetCode?

Most Visited Sector in a Circular Track (LeetCode #1560) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n) time complexity and O(n) space complexity. Key insight: The circular nature of the track allows for efficient counting of visits.

What is the time complexity of Most Visited Sector in a Circular Track?

The optimal solution for Most Visited Sector in a Circular Track runs in O(n) time and uses O(n) space. The time complexity is O(n) because we only iterate through the rounds and the sectors once, making it efficient for larger inputs.

What is the brute force solution for Most Visited Sector in a Circular Track?

The brute force approach for Most Visited Sector in a Circular Track is Brute Force, with O(n²) time complexity and O(1) space complexity. The brute force approach involves simulating each round and counting the number of visits to each sector. This is straightforward but inefficient for larger inputs. The optimal Optimal Solution approach improves this to O(n).

What algorithm or data structure is used to solve Most Visited Sector in a Circular Track?

Most Visited Sector in a Circular Track uses the following concepts: Array, Simulation. The recommended patterns to study are: Hash Map, Array.

What are the interview tips for Most Visited Sector in a Circular Track?

Clarify the problem and constraints before jumping into coding. Think about edge cases, such as the smallest and largest inputs. Discuss your thought process and approach before writing code.

What are common mistakes when solving Most Visited Sector in a Circular Track?

Not handling the circular wrap-around correctly. Overcomplicating the counting process instead of using a straightforward approach.

#1560

Most Visited Sector in a Circular Track

Easy

ArraySimulationHash MapArray

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(n)
Space	O(1)	O(n)

💡

Intuition

Time O(n)Space O(n)

The optimal approach takes advantage of the circular nature of the track and counts visits without explicitly iterating through every sector for each round. This reduces time complexity significantly.

⚙️

Algorithm

3 steps

1Step 1: Initialize an array to count visits for each sector.
2Step 2: For each round, calculate the number of sectors visited directly based on the start and end sectors.
3Step 3: Determine the maximum visit count and collect all sectors with that count.

solution.py17 lines

1# Full working Python code
2
3def most_visited(n, rounds):
4    visits = [0] * (n + 1)
5    for i in range(len(rounds) - 1):
6        start = rounds[i]
7        end = rounds[i + 1]
8        if start < end:
9            for j in range(start, end):
10                visits[j] += 1
11        else:
12            for j in range(start, n + 1):
13                visits[j] += 1
14            for j in range(1, end):
15                visits[j] += 1
16    max_visits = max(visits)
17    return [i for i in range(1, n + 1) if visits[i] == max_visits]

ℹ

Complexity note: The time complexity is O(n) because we only iterate through the rounds and the sectors once, making it efficient for larger inputs.

1The circular nature of the track allows for efficient counting of visits.
2The maximum visit count can be determined in a single pass after counting.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.