How do you solve Partition Array into Two Equal Product Subsets on LeetCode?

Partition Array into Two Equal Product Subsets (LeetCode #3566) can be solved using Brute Force. The optimal approach is Brute Force with undefined time complexity and undefined space complexity. Key insight: We can generate all possible subsets of the array and check if any two non-empty subsets have the same product equal to the target. This is straightforward but inefficient.

What is the time complexity of Partition Array into Two Equal Product Subsets?

The optimal solution for Partition Array into Two Equal Product Subsets runs in undefined time and uses undefined space. undefined

What algorithm or data structure is used to solve Partition Array into Two Equal Product Subsets?

Partition Array into Two Equal Product Subsets uses the following concepts: Array, Bit Manipulation, Recursion, Enumeration. The recommended patterns to study are: .

#3566

Partition Array into Two Equal Product Subsets

Medium

ArrayBit ManipulationRecursionEnumeration

LeetCode ↗

Approaches

💡

Intuition

Time Space

We can generate all possible subsets of the array and check if any two non-empty subsets have the same product equal to the target. This is straightforward but inefficient.

⚙️

Algorithm

3 steps

1Step 1: Generate all possible subsets of the array using bit manipulation.
2Step 2: For each subset, calculate its product.
3Step 3: Check if there exists another subset with the same product equal to target.

solution.py21 lines

1from itertools import combinations
2
3def can_partition(nums, target):
4    n = len(nums)
5    for i in range(1, 1 << n):
6        subset1 = [nums[j] for j in range(n) if (i & (1 << j))]
7        if len(subset1) == 0 or len(subset1) == n:
8            continue
9        product1 = 1
10        for num in subset1:
11            product1 *= num
12        if product1 == target:
13            for j in range(1, 1 << n):
14                if j & i == 0:
15                    subset2 = [nums[k] for k in range(n) if (j & (1 << k))]
16                    product2 = 1
17                    for num in subset2:
18                        product2 *= num
19                    if product2 == target:
20                        return True
21    return False

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