#1324
Print Words Vertically
MediumArrayStringSimulationArrayString Manipulation
Approaches
Brute ForceOptimal
Complexity Comparison
| Brute Force | Optimal Solution★ | |
|---|---|---|
| Time | O(n²) | O(n) |
| Space | O(1) | O(n) |
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Intuition
Time O(n)Space O(n)
The optimal solution builds on the brute force approach but uses a more efficient way to handle the vertical construction by directly using a list of strings to store the vertical words, avoiding unnecessary string concatenation.
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Algorithm
3 steps- 1Step 1: Split the string into words.
- 2Step 2: Create a list of empty strings for each vertical word.
- 3Step 3: Iterate through each word and character, appending characters to the corresponding vertical word string.
solution.py11 lines
1def printVertically(s):
2 words = s.split()
3 max_length = max(len(word) for word in words)
4 result = [''] * max_length
5 for word in words:
6 for i in range(max_length):
7 if i < len(word):
8 result[i] += word[i]
9 else:
10 result[i] += ' '
11 return [word.rstrip() for word in result]ℹ
Complexity note: The time complexity is O(n) because we iterate through each character of the words exactly once. The space complexity is O(n) due to the storage of the result strings.
- 1Understanding how to handle spaces is crucial for formatting the output correctly.
- 2Recognizing the maximum length of words helps in determining the vertical structure.
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