How do you solve Reorganize String on LeetCode?

Reorganize String (LeetCode #767) can be solved using Brute Force. The optimal approach is Brute Force with undefined time complexity and undefined space complexity. Key insight: The brute force approach involves generating all possible permutations of the string and checking if any of them meet the requirement of no two adjacent characters being the same. This is straightforward but inefficient.

What is the time complexity of Reorganize String?

The optimal solution for Reorganize String runs in undefined time and uses undefined space. undefined

#767

Reorganize String

Medium

Hash TableStringGreedySortingHeap (Priority Queue)Counting

LeetCode ↗

Approaches

💡

Intuition

Time Space

The brute force approach involves generating all possible permutations of the string and checking if any of them meet the requirement of no two adjacent characters being the same. This is straightforward but inefficient.

⚙️

Algorithm

3 steps

1Step 1: Generate all permutations of the string.
2Step 2: Check each permutation to see if it has adjacent characters that are the same.
3Step 3: Return the first valid permutation found, or return an empty string if none are valid.

solution.py7 lines

1from itertools import permutations
2
3def reorganizeString(s):
4    for perm in set(permutations(s)):
5        if all(perm[i] != perm[i + 1] for i in range(len(perm) - 1)):
6            return ''.join(perm)
7    return ''

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.