How do you solve Reverse Words With Same Vowel Count on LeetCode?

Reverse Words With Same Vowel Count (LeetCode #3775) can be solved using Brute Force. The optimal approach is Brute Force with undefined time complexity and undefined space complexity. Key insight: Count vowels in the first word, then check each subsequent word. Reverse words with matching vowel counts.

What is the time complexity of Reverse Words With Same Vowel Count?

The optimal solution for Reverse Words With Same Vowel Count runs in undefined time and uses undefined space. undefined

What algorithm or data structure is used to solve Reverse Words With Same Vowel Count?

Reverse Words With Same Vowel Count uses the following concepts: Two Pointers, String, Simulation. The recommended patterns to study are: .

#3775

Reverse Words With Same Vowel Count

Medium

Two PointersStringSimulation

LeetCode ↗

Approaches

💡

Intuition

Time Space

Count vowels in the first word, then check each subsequent word. Reverse words with matching vowel counts.

⚙️

Algorithm

3 steps

1Step 1: Split the string into words.
2Step 2: Count vowels in the first word.
3Step 3: For each following word, reverse it if it has the same vowel count as the first word.

solution.py7 lines

1def reverseWords(s):
2    words = s.split()
3    first_vowel_count = sum(1 for c in words[0] if c in 'aeiou')
4    for i in range(1, len(words)):
5        if sum(1 for c in words[i] if c in 'aeiou') == first_vowel_count:
6            words[i] = words[i][::-1]
7    return ' '.join(words)

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