#1672

Richest Customer Wealth

Easy
ArrayMatrixArrayMatrix
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Approaches

Brute ForceOptimal
Complexity Comparison
Brute ForceOptimal Solution
Time
O(n²)
O(n)
Space
O(1)
O(1)
💡

Intuition

Time O(n)Space O(1)

The optimal solution leverages the same summation logic but focuses on reducing unnecessary calculations. By maintaining a running maximum wealth during the summation process, we can achieve the result in a single pass through the data.

⚙️

Algorithm

5 steps
  1. 1Step 1: Initialize a variable to keep track of the maximum wealth.
  2. 2Step 2: Iterate through each customer in the accounts array.
  3. 3Step 3: For each customer, sum their bank accounts and immediately compare to the current maximum wealth.
  4. 4Step 4: Update the maximum wealth if the current customer's wealth exceeds it.
  5. 5Step 5: Return the maximum wealth after checking all customers.
solution.py2 lines
1def maximumWealth(accounts):
2    return max(map(sum, accounts))

Complexity note: The time complexity is O(n) because we only iterate through the accounts once. The space complexity is O(1) since we only use a constant amount of space for the maximum wealth variable.

  • 1Wealth is calculated by summing up bank accounts for each customer.
  • 2The maximum wealth can be found by comparing sums efficiently.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.