#197

Rising Temperature

Easy
DatabaseSelf-JoinDate Manipulation
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Approaches

Brute ForceOptimal
Complexity Comparison
Brute ForceOptimal Solution
Time
O(n²)
O(n)
Space
O(1)
O(n)
💡

Intuition

Time O(n)Space O(n)

The optimal solution uses a self-join to efficiently compare each day's temperature with the previous day's temperature, reducing the number of comparisons needed.

⚙️

Algorithm

3 steps
  1. 1Step 1: Use a self-join on the Weather table to connect each record with its previous day's record.
  2. 2Step 2: Filter the results where the current day's temperature is greater than the previous day's temperature.
  3. 3Step 3: Select the id of the records that meet the criteria.
solution.py1 lines
1SELECT w1.id FROM Weather w1 JOIN Weather w2 ON DATE_ADD(w2.recordDate, INTERVAL 1 DAY) = w1.recordDate WHERE w1.temperature > w2.temperature;

Complexity note: This complexity is linear because each record is processed a constant number of times, and we only store results for qualifying records.

  • 1Understanding how to use self-joins can significantly optimize queries involving comparisons.
  • 2Recognizing patterns in data (like daily temperatures) can help in structuring queries effectively.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.