#3678

Smallest Absent Positive Greater Than Average

Easy
ArrayHash TableHash MapArray
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Approaches

Brute ForceOptimal
Complexity Comparison
Brute ForceOptimal Solution
Time
O(n²)
O(n)
Space
O(1)
O(n)
💡

Intuition

Time O(n)Space O(n)

Use a set to track existing numbers for quick lookup, then find the smallest absent positive integer greater than the average.

⚙️

Algorithm

3 steps
  1. 1Step 1: Calculate the average of nums.
  2. 2Step 2: Store all positive integers in a set for O(1) lookup.
  3. 3Step 3: Start from floor(avg) + 1 and find the first integer not in the set.
solution.py7 lines
1def smallestAbsent(nums):
2    avg = sum(nums) / len(nums)
3    num_set = set(nums)
4    x = int(avg) + 1
5    while x in num_set:
6        x += 1
7    return x

Complexity note: The complexity is linear due to the single pass to create the set and another pass to find the absent integer.

  • 1Using a set allows for faster lookups.
  • 2The average helps to limit the search space for the absent integer.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.