How do you solve Sort the Jumbled Numbers on LeetCode?

Sort the Jumbled Numbers (LeetCode #2191) can be solved using Brute Force or Optimal Solution. The optimal approach is Optimal Solution with O(n log n) time complexity and O(n) space complexity. Key insight: Mapping digits correctly is crucial for accurate sorting.

What is the brute force solution for Sort the Jumbled Numbers?

The brute force approach for Sort the Jumbled Numbers is Brute Force, with O(n²) time complexity and O(n) space complexity. The brute force approach involves mapping each number in the input array to its corresponding mapped value according to the mapping array. Then, we sort the numbers based on these mapped values while maintaining their original order for numbers with the same mapped value. The optimal Optimal Solution approach improves this to O(n log n).

What algorithm or data structure is used to solve Sort the Jumbled Numbers?

Sort the Jumbled Numbers uses the following concepts: Array, Sorting. The recommended patterns to study are: Hash Map, Array.

What are the interview tips for Sort the Jumbled Numbers?

Always clarify the requirements and constraints before jumping into coding. Think about edge cases, such as all digits being the same or having leading zeros. Practice explaining your thought process while coding, as it helps in interviews.

What are common mistakes when solving Sort the Jumbled Numbers?

Not handling leading zeros in the mapped values. Forgetting to maintain the original order when mapped values are equal.

#2191

Sort the Jumbled Numbers

Medium

ArraySortingHash MapArray

LeetCode ↗

Approaches

Brute ForceOptimal

Complexity Comparison

	Brute Force	Optimal Solution★
Time	O(n²)	O(n log n)
Space	O(n)	O(n)

💡

Intuition

Time O(n log n)Space O(n)

The optimal solution efficiently maps and sorts the numbers in a single pass using a custom sort function. This approach minimizes the number of passes over the data and leverages Python's built-in sorting capabilities, ensuring we maintain the original order for equal mapped values.

⚙️

Algorithm

3 steps

1Step 1: Create a function to map each digit of a number using the mapping array.
2Step 2: Use the built-in sort function with a custom key that maps the numbers and maintains their original indices.
3Step 3: Return the sorted numbers based on their mapped values.

solution.py12 lines

1# Full working Python code
2
3def map_number(num, mapping):
4    return int(''.join(str(mapping[int(digit)]) for digit in str(num)))
5
6def sort_jumbled_numbers(mapping, nums):
7    return sorted(nums, key=lambda x: (map_number(x, mapping), nums.index(x)))
8
9# Example usage
10mapping = [8,9,4,0,2,1,3,5,7,6]
11nums = [991,338,38]
12print(sort_jumbled_numbers(mapping, nums))

ℹ

Complexity note: The time complexity is O(n log n) due to the sorting step. The mapping of each number is O(n), but since sorting dominates the complexity, the overall complexity is O(n log n).

1Mapping digits correctly is crucial for accurate sorting.
2Maintaining relative order for equal mapped values can be achieved using indices.

Solutions and explanations are original Tejav content. Problem titles © LeetCode — use the LeetCode button above for the full problem statement.