Class 10 Mathematics
Tangents & Secants
⏱ 12 min read
In this chapter, we will explore the concepts of tangents and secants in relation to circles. Understanding these concepts is crucial for solving various geometric problems. We will discuss definitions, properties, and the relationships between tangents, secants, and circles, along with examples to solidify your understanding.
A secant divides the circle into two arcs. The longer arc is called the major arc, and the shorter arc is the minor arc.
The angle formed between a secant and a tangent drawn from the same external point is equal to half the difference of the intercepted arcs. This can be stated as: If a tangent touches the circle at point A and a secant intersects the circle at points B and C, then:
[ \angle TAB = \frac{1}{2} (arc BC - arc AC) ]
The Power of a Point Theorem states that for a point outside a circle, the square of the length of the tangent drawn from that point to the circle is equal to the product of the lengths of the segments of the secant line that intersect the circle. Mathematically, if point P is outside the circle and tangent PT is drawn to touch the circle at T, while secant PB intersects the circle at points A and C, then:
[ PT^2 = PA \times PC ]
Consider a circle with a radius of 5 cm and a point P located 13 cm away from the center O of the circle. To find the length of the tangent PT from point P to the circle, we can use the Pythagorean theorem:
[ OP^2 = OT^2 + PT^2 ]
Where OP = 13 cm, OT = 5 cm (radius), and PT is the length of the tangent. Thus:
[ 13^2 = 5^2 + PT^2 ] [ 169 = 25 + PT^2 ] [ PT^2 = 169 - 25 = 144 ] [ PT = \sqrt{144} = 12 \text{ cm} ]
So, the length of the tangent is 12 cm.
Let’s say point P is outside a circle, and the lengths of segments PA and PC (where A and C are points where the secant intersects the circle) are 4 cm and 6 cm respectively. To find the length of the tangent PT from point P to the circle, we can use the Power of a Point theorem:
[ PT^2 = PA \times PC ] [ PT^2 = 4 \times 6 = 24 ] [ PT = \sqrt{24} = 2\sqrt{6} \text{ cm} ]
In this chapter, we have learned about tangents and secants in relation to circles. We defined both terms, discussed their properties, and explored important relationships between them. We also applied these concepts through examples, demonstrating how to find the lengths of tangents and utilize the Power of a Point theorem. Mastering these concepts is essential for solving various problems in geometry. Understanding tangents and secants will not only enhance your mathematical skills but also prepare you for more advanced topics in mathematics.
By grasping these core concepts, you will be well-equipped to tackle problems involving circles in your future studies.
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